(4x+1/3)+(2x+1/2)-(3x-7/5)=6

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Solution for (4x+1/3)+(2x+1/2)-(3x-7/5)=6 equation:



(4x+1/3)+(2x+1/2)-(3x-7/5)=6
We move all terms to the left:
(4x+1/3)+(2x+1/2)-(3x-7/5)-(6)=0
We add all the numbers together, and all the variables
(+4x+1/3)+(+2x+1/2)-(+3x-7/5)-6=0
We get rid of parentheses
4x+2x-3x-6+1/3+1/2+7/5=0
We calculate fractions
There is no solution for this equation

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