(4x+1/3)+(2x-1/2)-(3x-7/5)=6

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Solution for (4x+1/3)+(2x-1/2)-(3x-7/5)=6 equation: 



(4x+1/3)+(2x-1/2)-(3x-7/5)=6

We move all terms to the left:

(4x+1/3)+(2x-1/2)-(3x-7/5)-(6)=0

We add all the numbers together, and all the variables

(+4x+1/3)+(+2x-1/2)-(+3x-7/5)-6=0

We get rid of parentheses

4x+2x-3x-6+1/3-1/2+7/5=0

We calculate fractions

There is no solution for this equation

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