(4x+10)+(3x-5)+(x-5)=180

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Solution for (4x+10)+(3x-5)+(x-5)=180 equation: 



(4x+10)+(3x-5)+(x-5)=180

We move all terms to the left:

(4x+10)+(3x-5)+(x-5)-(180)=0

We get rid of parentheses

4x+3x+x+10-5-5-180=0

We add all the numbers together, and all the variables

8x-180=0

We move all terms containing x to the left, all other terms to the right

8x=180

x=180/8

x=22+1/2

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