(4x+10)+(3x-5)+(x-5)=180

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Solution for (4x+10)+(3x-5)+(x-5)=180 equation:



(4x+10)+(3x-5)+(x-5)=180
We move all terms to the left:
(4x+10)+(3x-5)+(x-5)-(180)=0
We get rid of parentheses
4x+3x+x+10-5-5-180=0
We add all the numbers together, and all the variables
8x-180=0
We move all terms containing x to the left, all other terms to the right
8x=180
x=180/8
x=22+1/2

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