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(4x+12)(x+12)=x
We move all terms to the left:
(4x+12)(x+12)-(x)=0
We add all the numbers together, and all the variables
-1x+(4x+12)(x+12)=0
We multiply parentheses ..
(+4x^2+48x+12x+144)-1x=0
We get rid of parentheses
4x^2+48x+12x-1x+144=0
We add all the numbers together, and all the variables
4x^2+59x+144=0
a = 4; b = 59; c = +144;
Δ = b2-4ac
Δ = 592-4·4·144
Δ = 1177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-\sqrt{1177}}{2*4}=\frac{-59-\sqrt{1177}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+\sqrt{1177}}{2*4}=\frac{-59+\sqrt{1177}}{8} $
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