(4x+12)-(x)(x)+3x-4=7x

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Solution for (4x+12)-(x)(x)+3x-4=7x equation: 


Simplifying
(4x + 12) + -1(x)(x) + 3x + -4 = 7x

Reorder the terms:
(12 + 4x) + -1(x)(x) + 3x + -4 = 7x

Remove parenthesis around (12 + 4x)
12 + 4x + -1(x)(x) + 3x + -4 = 7x

Multiply x * x
12 + 4x + -1x2 + 3x + -4 = 7x

Reorder the terms:
12 + -4 + 4x + 3x + -1x2 = 7x

Combine like terms: 12 + -4 = 8
8 + 4x + 3x + -1x2 = 7x

Combine like terms: 4x + 3x = 7x
8 + 7x + -1x2 = 7x

Add '-7x' to each side of the equation.
8 + 7x + -7x + -1x2 = 7x + -7x

Combine like terms: 7x + -7x = 0
8 + 0 + -1x2 = 7x + -7x
8 + -1x2 = 7x + -7x

Combine like terms: 7x + -7x = 0
8 + -1x2 = 0

Solving
8 + -1x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -1x2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -1x2 = 0 + -8
-1x2 = 0 + -8

Combine like terms: 0 + -8 = -8
-1x2 = -8

Divide each side by '-1'.
x2 = 8

Simplifying
x2 = 8

Take the square root of each side:
x = {-2.828427125, 2.828427125}

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