(4x+12)=(2x+17)+(7x+10)

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Solution for (4x+12)=(2x+17)+(7x+10) equation: 



(4x+12)=(2x+17)+(7x+10)

We move all terms to the left:

(4x+12)-((2x+17)+(7x+10))=0

We get rid of parentheses

4x-((2x+17)+(7x+10))+12=0



We calculate terms in parentheses: -((2x+17)+(7x+10)), so:

(2x+17)+(7x+10)

We get rid of parentheses

2x+7x+17+10

We add all the numbers together, and all the variables

9x+27

Back to the equation:

-(9x+27)



We get rid of parentheses

4x-9x-27+12=0

We add all the numbers together, and all the variables

-5x-15=0

We move all terms containing x to the left, all other terms to the right

-5x=15

x=15/-5

x=-3

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