(4x+12)=(2x+18)+(7x+25)

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Solution for (4x+12)=(2x+18)+(7x+25) equation: 



(4x+12)=(2x+18)+(7x+25)

We move all terms to the left:

(4x+12)-((2x+18)+(7x+25))=0

We get rid of parentheses

4x-((2x+18)+(7x+25))+12=0



We calculate terms in parentheses: -((2x+18)+(7x+25)), so:

(2x+18)+(7x+25)

We get rid of parentheses

2x+7x+18+25

We add all the numbers together, and all the variables

9x+43

Back to the equation:

-(9x+43)



We get rid of parentheses

4x-9x-43+12=0

We add all the numbers together, and all the variables

-5x-31=0

We move all terms containing x to the left, all other terms to the right

-5x=31

x=31/-5

x=-6+1/5

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