(4x+12)=112=68

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Solution for (4x+12)=112=68 equation: 



(4x+12)=112=68

We move all terms to the left:

(4x+12)-(112)=0

We get rid of parentheses

4x+12-112=0

We add all the numbers together, and all the variables

4x-100=0

We move all terms containing x to the left, all other terms to the right

4x=100

x=100/4

x=25

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