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(4x+15)(2x+65)=180
We move all terms to the left:
(4x+15)(2x+65)-(180)=0
We multiply parentheses ..
(+8x^2+260x+30x+975)-180=0
We get rid of parentheses
8x^2+260x+30x+975-180=0
We add all the numbers together, and all the variables
8x^2+290x+795=0
a = 8; b = 290; c = +795;
Δ = b2-4ac
Δ = 2902-4·8·795
Δ = 58660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{58660}=\sqrt{4*14665}=\sqrt{4}*\sqrt{14665}=2\sqrt{14665}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(290)-2\sqrt{14665}}{2*8}=\frac{-290-2\sqrt{14665}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(290)+2\sqrt{14665}}{2*8}=\frac{-290+2\sqrt{14665}}{16} $
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