(4x+15)=(2x+12)+(5x-12)

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Solution for (4x+15)=(2x+12)+(5x-12) equation: 



(4x+15)=(2x+12)+(5x-12)

We move all terms to the left:

(4x+15)-((2x+12)+(5x-12))=0

We get rid of parentheses

4x-((2x+12)+(5x-12))+15=0



We calculate terms in parentheses: -((2x+12)+(5x-12)), so:

(2x+12)+(5x-12)

We get rid of parentheses

2x+5x+12-12

We add all the numbers together, and all the variables

7x

Back to the equation:

-(7x)



We add all the numbers together, and all the variables

-3x+15=0

We move all terms containing x to the left, all other terms to the right

-3x=-15

x=-15/-3

x=+5

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