(4x+15)=(2x+29)

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Solution for (4x+15)=(2x+29) equation: 



(4x+15)=(2x+29)

We move all terms to the left:

(4x+15)-((2x+29))=0

We get rid of parentheses

4x-((2x+29))+15=0



We calculate terms in parentheses: -((2x+29)), so:

(2x+29)

We get rid of parentheses

2x+29

Back to the equation:

-(2x+29)



We get rid of parentheses

4x-2x-29+15=0

We add all the numbers together, and all the variables

2x-14=0

We move all terms containing x to the left, all other terms to the right

2x=14

x=14/2

x=7

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