(4x+16)(2x-8)=0

Solution for (4x+16)(2x-8)=0 equation:

Simplifying
(4x + 16)(2x + -8) = 0

Reorder the terms:
(16 + 4x)(2x + -8) = 0

Reorder the terms:
(16 + 4x)(-8 + 2x) = 0

Multiply (16 + 4x) * (-8 + 2x)
(16(-8 + 2x) + 4x * (-8 + 2x)) = 0
((-8 * 16 + 2x * 16) + 4x * (-8 + 2x)) = 0
((-128 + 32x) + 4x * (-8 + 2x)) = 0
(-128 + 32x + (-8 * 4x + 2x * 4x)) = 0
(-128 + 32x + (-32x + 8x2)) = 0

Combine like terms: 32x + -32x = 0
(-128 + 0 + 8x2) = 0
(-128 + 8x2) = 0

Solving
-128 + 8x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '128' to each side of the equation.
-128 + 128 + 8x2 = 0 + 128

Combine like terms: -128 + 128 = 0
0 + 8x2 = 0 + 128
8x2 = 0 + 128

Combine like terms: 0 + 128 = 128
8x2 = 128

Divide each side by '8'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}