(4x+16)(5x-11)=0

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Solution for (4x+16)(5x-11)=0 equation:



(4x+16)(5x-11)=0
We multiply parentheses ..
(+20x^2-44x+80x-176)=0
We get rid of parentheses
20x^2-44x+80x-176=0
We add all the numbers together, and all the variables
20x^2+36x-176=0
a = 20; b = 36; c = -176;
Δ = b2-4ac
Δ = 362-4·20·(-176)
Δ = 15376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15376}=124$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-124}{2*20}=\frac{-160}{40} =-4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+124}{2*20}=\frac{88}{40} =2+1/5 $

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