(4x+2)(3x)=74

Solution for (4x+2)(3x)=74 equation:

(4x+2)(3x)=74

We move all terms to the left:

(4x+2)(3x)-(74)=0

We multiply parentheses

12x^2+6x-74=0

a = 12; b = 6; c = -74;
Δ = b2-4ac
Δ = 62-4·12·(-74)
Δ = 3588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3588}=\sqrt{4*897}=\sqrt{4}*\sqrt{897}=2\sqrt{897}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{897}}{2*12}=\frac{-6-2\sqrt{897}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{897}}{2*12}=\frac{-6+2\sqrt{897}}{24}
$