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(4x+2)(x+2)=130
We move all terms to the left:
(4x+2)(x+2)-(130)=0
We multiply parentheses ..
(+4x^2+8x+2x+4)-130=0
We get rid of parentheses
4x^2+8x+2x+4-130=0
We add all the numbers together, and all the variables
4x^2+10x-126=0
a = 4; b = 10; c = -126;
Δ = b2-4ac
Δ = 102-4·4·(-126)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-46}{2*4}=\frac{-56}{8} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+46}{2*4}=\frac{36}{8} =4+1/2 $
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