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(4x+2)(x+3)=0
We multiply parentheses ..
(+4x^2+12x+2x+6)=0
We get rid of parentheses
4x^2+12x+2x+6=0
We add all the numbers together, and all the variables
4x^2+14x+6=0
a = 4; b = 14; c = +6;
Δ = b2-4ac
Δ = 142-4·4·6
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-10}{2*4}=\frac{-24}{8} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+10}{2*4}=\frac{-4}{8} =-1/2 $
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