(4x+2)+(3x+14)=9(x-14)

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Solution for (4x+2)+(3x+14)=9(x-14) equation: 



(4x+2)+(3x+14)=9(x-14)

We move all terms to the left:

(4x+2)+(3x+14)-(9(x-14))=0

We get rid of parentheses

4x+3x-(9(x-14))+2+14=0



We calculate terms in parentheses: -(9(x-14)), so:

9(x-14)

We multiply parentheses

9x-126

Back to the equation:

-(9x-126)



We add all the numbers together, and all the variables

7x-(9x-126)+16=0

We get rid of parentheses

7x-9x+126+16=0

We add all the numbers together, and all the variables

-2x+142=0

We move all terms containing x to the left, all other terms to the right

-2x=-142

x=-142/-2

x=+71

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