(4x+2)+(3x-5)+(2x+10)=145

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Solution for (4x+2)+(3x-5)+(2x+10)=145 equation: 



(4x+2)+(3x-5)+(2x+10)=145

We move all terms to the left:

(4x+2)+(3x-5)+(2x+10)-(145)=0

We get rid of parentheses

4x+3x+2x+2-5+10-145=0

We add all the numbers together, and all the variables

9x-138=0

We move all terms containing x to the left, all other terms to the right

9x=138

x=138/9

x=15+1/3

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