(4x+2)+(3x-7)=(9x-45)

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Solution for (4x+2)+(3x-7)=(9x-45) equation: 



(4x+2)+(3x-7)=(9x-45)

We move all terms to the left:

(4x+2)+(3x-7)-((9x-45))=0

We get rid of parentheses

4x+3x-((9x-45))+2-7=0



We calculate terms in parentheses: -((9x-45)), so:

(9x-45)

We get rid of parentheses

9x-45

Back to the equation:

-(9x-45)



We add all the numbers together, and all the variables

7x-(9x-45)-5=0

We get rid of parentheses

7x-9x+45-5=0

We add all the numbers together, and all the variables

-2x+40=0

We move all terms containing x to the left, all other terms to the right

-2x=-40

x=-40/-2

x=+20

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