(4x+2)+(3x-7)=131

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Solution for (4x+2)+(3x-7)=131 equation: 



(4x+2)+(3x-7)=131

We move all terms to the left:

(4x+2)+(3x-7)-(131)=0

We get rid of parentheses

4x+3x+2-7-131=0

We add all the numbers together, and all the variables

7x-136=0

We move all terms containing x to the left, all other terms to the right

7x=136

x=136/7

x=19+3/7

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