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(4x+2)+(3x-7)=135
We move all terms to the left:
(4x+2)+(3x-7)-(135)=0
We get rid of parentheses
4x+3x+2-7-135=0
We add all the numbers together, and all the variables
7x-140=0
We move all terms containing x to the left, all other terms to the right
7x=140
x=140/7
x=20
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