(4x+2)+(4x+2)+(3x+3)+(3x+3)=150

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Solution for (4x+2)+(4x+2)+(3x+3)+(3x+3)=150 equation: 



(4x+2)+(4x+2)+(3x+3)+(3x+3)=150

We move all terms to the left:

(4x+2)+(4x+2)+(3x+3)+(3x+3)-(150)=0

We get rid of parentheses

4x+4x+3x+3x+2+2+3+3-150=0

We add all the numbers together, and all the variables

14x-140=0

We move all terms containing x to the left, all other terms to the right

14x=140

x=140/14

x=10

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