(4x+2)+132+128+(4x-10)+(5x-11)=540

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Solution for (4x+2)+132+128+(4x-10)+(5x-11)=540 equation: 



(4x+2)+132+128+(4x-10)+(5x-11)=540

We move all terms to the left:

(4x+2)+132+128+(4x-10)+(5x-11)-(540)=0

We add all the numbers together, and all the variables

(4x+2)+(4x-10)+(5x-11)-280=0

We get rid of parentheses

4x+4x+5x+2-10-11-280=0

We add all the numbers together, and all the variables

13x-299=0

We move all terms containing x to the left, all other terms to the right

13x=299

x=299/13

x=23

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