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(4x+2)-12x-8=16-10x+6
We move all terms to the left:
(4x+2)-12x-8-(16-10x+6)=0
We add all the numbers together, and all the variables
(4x+2)-12x-(-10x+22)-8=0
We add all the numbers together, and all the variables
-12x+(4x+2)-(-10x+22)-8=0
We get rid of parentheses
-12x+4x+10x+2-22-8=0
We add all the numbers together, and all the variables
2x-28=0
We move all terms containing x to the left, all other terms to the right
2x=28
x=28/2
x=14
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