(4x+2)/6=x-7

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Solution for (4x+2)/6=x-7 equation:



(4x+2)/6=x-7
We move all terms to the left:
(4x+2)/6-(x-7)=0
We get rid of parentheses
(4x+2)/6-x+7=0
We multiply all the terms by the denominator
(4x+2)-x*6+7*6=0
We add all the numbers together, and all the variables
(4x+2)-x*6+42=0
Wy multiply elements
(4x+2)-6x+42=0
We get rid of parentheses
4x-6x+2+42=0
We add all the numbers together, and all the variables
-2x+44=0
We move all terms containing x to the left, all other terms to the right
-2x=-44
x=-44/-2
x=+22

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