(4x+2)=19x+3-3x+5

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Solution for (4x+2)=19x+3-3x+5 equation:



(4x+2)=19x+3-3x+5
We move all terms to the left:
(4x+2)-(19x+3-3x+5)=0
We add all the numbers together, and all the variables
(4x+2)-(16x+8)=0
We get rid of parentheses
4x-16x+2-8=0
We add all the numbers together, and all the variables
-12x-6=0
We move all terms containing x to the left, all other terms to the right
-12x=6
x=6/-12
x=-1/2

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