(4x+2)x=210

Solution for (4x+2)x=210 equation:

(4x+2)x=210

We move all terms to the left:

(4x+2)x-(210)=0

We multiply parentheses

4x^2+2x-210=0

a = 4; b = 2; c = -210;
Δ = b2-4ac
Δ = 22-4·4·(-210)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-58}{2*4}=\frac{-60}{8}
=-7+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+58}{2*4}=\frac{56}{8}
=7
$