(4x+20)+(4x+20)=(3x+30)

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Solution for (4x+20)+(4x+20)=(3x+30) equation: 



(4x+20)+(4x+20)=(3x+30)

We move all terms to the left:

(4x+20)+(4x+20)-((3x+30))=0

We get rid of parentheses

4x+4x-((3x+30))+20+20=0



We calculate terms in parentheses: -((3x+30)), so:

(3x+30)

We get rid of parentheses

3x+30

Back to the equation:

-(3x+30)



We add all the numbers together, and all the variables

8x-(3x+30)+40=0

We get rid of parentheses

8x-3x-30+40=0

We add all the numbers together, and all the variables

5x+10=0

We move all terms containing x to the left, all other terms to the right

5x=-10

x=-10/5

x=-2

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