(4x+20)+79=12x+3

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Solution for (4x+20)+79=12x+3 equation: 



(4x+20)+79=12x+3

We move all terms to the left:

(4x+20)+79-(12x+3)=0

We get rid of parentheses

4x-12x+20-3+79=0

We add all the numbers together, and all the variables

-8x+96=0

We move all terms containing x to the left, all other terms to the right

-8x=-96

x=-96/-8

x=+12

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