(4x+20)+79=12x+5

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Solution for (4x+20)+79=12x+5 equation: 



(4x+20)+79=12x+5

We move all terms to the left:

(4x+20)+79-(12x+5)=0

We get rid of parentheses

4x-12x+20-5+79=0

We add all the numbers together, and all the variables

-8x+94=0

We move all terms containing x to the left, all other terms to the right

-8x=-94

x=-94/-8

x=11+3/4

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