(4x+20)/(3x+15)

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Solution for (4x+20)/(3x+15) equation: 


D( x )

3*x+15 = 0

3*x+15 = 0

3*x+15 = 0

3*x+15 = 0 // - 15

3*x = -15 // : 3

x = -15/3

x = -5

x in (-oo:-5) U (-5:+oo)

(4*x+20)/(3*x+15) = 0

4*x+20 = 0 // - 20

4*x = -20 // : 4

x = -20/4

x = -5

x in { -5} 

x belongs to the empty set

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