(4x+20)=(3x+21)

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Solution for (4x+20)=(3x+21) equation: 



(4x+20)=(3x+21)

We move all terms to the left:

(4x+20)-((3x+21))=0

We get rid of parentheses

4x-((3x+21))+20=0



We calculate terms in parentheses: -((3x+21)), so:

(3x+21)

We get rid of parentheses

3x+21

Back to the equation:

-(3x+21)



We get rid of parentheses

4x-3x-21+20=0

We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1

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