(4x+20)=(3x+50)

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Solution for (4x+20)=(3x+50) equation: 



(4x+20)=(3x+50)

We move all terms to the left:

(4x+20)-((3x+50))=0

We get rid of parentheses

4x-((3x+50))+20=0



We calculate terms in parentheses: -((3x+50)), so:

(3x+50)

We get rid of parentheses

3x+50

Back to the equation:

-(3x+50)



We get rid of parentheses

4x-3x-50+20=0

We add all the numbers together, and all the variables

x-30=0

We move all terms containing x to the left, all other terms to the right

x=30

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