(4x+25)(16x-48)=0

Solution for (4x+25)(16x-48)=0 equation:

(4x+25)(16x-48)=0

We multiply parentheses ..

(+64x^2-192x+400x-1200)=0

We get rid of parentheses

64x^2-192x+400x-1200=0

We add all the numbers together, and all the variables

64x^2+208x-1200=0

a = 64; b = 208; c = -1200;
Δ = b2-4ac
Δ = 2082-4·64·(-1200)
Δ = 350464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{350464}=592$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(208)-592}{2*64}=\frac{-800}{128}
=-6+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(208)+592}{2*64}=\frac{384}{128}
=3
$