(4x+3)(13x=10)

Solution for (4x+3)(13x=10) equation:

(4x+3)(13x=10)

We move all terms to the left:

(4x+3)(13x-(10))=0

We multiply parentheses ..

(+52x^2-40x+39x-30)=0

We get rid of parentheses

52x^2-40x+39x-30=0

We add all the numbers together, and all the variables

52x^2-1x-30=0

a = 52; b = -1; c = -30;
Δ = b2-4ac
Δ = -12-4·52·(-30)
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6241}=79$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-79}{2*52}=\frac{-78}{104}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+79}{2*52}=\frac{80}{104}
=10/13
$