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(4x+3)(3x+8)=0
We multiply parentheses ..
(+12x^2+32x+9x+24)=0
We get rid of parentheses
12x^2+32x+9x+24=0
We add all the numbers together, and all the variables
12x^2+41x+24=0
a = 12; b = 41; c = +24;
Δ = b2-4ac
Δ = 412-4·12·24
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-23}{2*12}=\frac{-64}{24} =-2+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+23}{2*12}=\frac{-18}{24} =-3/4 $
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