(4x+3)*(2x+4)=0

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Solution for (4x+3)*(2x+4)=0 equation:



(4x+3)(2x+4)=0
We multiply parentheses ..
(+8x^2+16x+6x+12)=0
We get rid of parentheses
8x^2+16x+6x+12=0
We add all the numbers together, and all the variables
8x^2+22x+12=0
a = 8; b = 22; c = +12;
Δ = b2-4ac
Δ = 222-4·8·12
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-10}{2*8}=\frac{-32}{16} =-2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+10}{2*8}=\frac{-12}{16} =-3/4 $

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