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(4x+3)(2x+4)=0
We multiply parentheses ..
(+8x^2+16x+6x+12)=0
We get rid of parentheses
8x^2+16x+6x+12=0
We add all the numbers together, and all the variables
8x^2+22x+12=0
a = 8; b = 22; c = +12;
Δ = b2-4ac
Δ = 222-4·8·12
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-10}{2*8}=\frac{-32}{16} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+10}{2*8}=\frac{-12}{16} =-3/4 $
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