(4x+3)+(10x-18)=90x

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Solution for (4x+3)+(10x-18)=90x equation: 



(4x+3)+(10x-18)=90x

We move all terms to the left:

(4x+3)+(10x-18)-(90x)=0

We add all the numbers together, and all the variables

-90x+(4x+3)+(10x-18)=0

We get rid of parentheses

-90x+4x+10x+3-18=0

We add all the numbers together, and all the variables

-76x-15=0

We move all terms containing x to the left, all other terms to the right

-76x=15

x=15/-76

x=-15/76

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