(4x+3)+(3x-5)=19

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Solution for (4x+3)+(3x-5)=19 equation: 



(4x+3)+(3x-5)=19

We move all terms to the left:

(4x+3)+(3x-5)-(19)=0

We get rid of parentheses

4x+3x+3-5-19=0

We add all the numbers together, and all the variables

7x-21=0

We move all terms containing x to the left, all other terms to the right

7x=21

x=21/7

x=3

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