(4x+3)+(4x+2)+(4x)=(4x)+(4x)+(5x+1)

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Solution for (4x+3)+(4x+2)+(4x)=(4x)+(4x)+(5x+1) equation:



(4x+3)+(4x+2)+(4x)=(4x)+(4x)+(5x+1)
We move all terms to the left:
(4x+3)+(4x+2)+(4x)-((4x)+(4x)+(5x+1))=0
We add all the numbers together, and all the variables
4x+(4x+3)+(4x+2)-(4x+4x+(5x+1))=0
We get rid of parentheses
4x+4x+4x-(4x+4x+(5x+1))+3+2=0
We calculate terms in parentheses: -(4x+4x+(5x+1)), so:
4x+4x+(5x+1)
We add all the numbers together, and all the variables
8x+(5x+1)
We get rid of parentheses
8x+5x+1
We add all the numbers together, and all the variables
13x+1
Back to the equation:
-(13x+1)
We add all the numbers together, and all the variables
12x-(13x+1)+5=0
We get rid of parentheses
12x-13x-1+5=0
We add all the numbers together, and all the variables
-1x+4=0
We move all terms containing x to the left, all other terms to the right
-x=-4
x=-4/-1
x=+4

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