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(4x+3)+(4x+3)=(12)
We move all terms to the left:
(4x+3)+(4x+3)-((12))=0
determiningTheFunctionDomain (4x+3)+(4x+3)-12=0
We get rid of parentheses
4x+4x+3+3-12=0
We add all the numbers together, and all the variables
8x-6=0
We move all terms containing x to the left, all other terms to the right
8x=6
x=6/8
x=3/4
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