(4x+3)+(6x+19)+58=180

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Solution for (4x+3)+(6x+19)+58=180 equation: 



(4x+3)+(6x+19)+58=180

We move all terms to the left:

(4x+3)+(6x+19)+58-(180)=0

We add all the numbers together, and all the variables

(4x+3)+(6x+19)-122=0

We get rid of parentheses

4x+6x+3+19-122=0

We add all the numbers together, and all the variables

10x-100=0

We move all terms containing x to the left, all other terms to the right

10x=100

x=100/10

x=10

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