(4x+3)+(6x+3)=(9x+12)

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Solution for (4x+3)+(6x+3)=(9x+12) equation:



(4x+3)+(6x+3)=(9x+12)
We move all terms to the left:
(4x+3)+(6x+3)-((9x+12))=0
We get rid of parentheses
4x+6x-((9x+12))+3+3=0
We calculate terms in parentheses: -((9x+12)), so:
(9x+12)
We get rid of parentheses
9x+12
Back to the equation:
-(9x+12)
We add all the numbers together, and all the variables
10x-(9x+12)+6=0
We get rid of parentheses
10x-9x-12+6=0
We add all the numbers together, and all the variables
x-6=0
We move all terms containing x to the left, all other terms to the right
x=6

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