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(4x+3)/(2x+5)=x
We move all terms to the left:
(4x+3)/(2x+5)-(x)=0
Domain of the equation: (2x+5)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x!=-5
x!=-5/2
x!=-2+1/2
x∈R
-1x+(4x+3)/(2x+5)=0
We multiply all the terms by the denominator
-1x*(2x+5)+(4x+3)=0
We multiply parentheses
-2x^2-5x+(4x+3)=0
We get rid of parentheses
-2x^2-5x+4x+3=0
We add all the numbers together, and all the variables
-2x^2-1x+3=0
a = -2; b = -1; c = +3;
Δ = b2-4ac
Δ = -12-4·(-2)·3
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-5}{2*-2}=\frac{-4}{-4} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+5}{2*-2}=\frac{6}{-4} =-1+1/2 $
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