(4x+3)/2+x=(5x+4)/4

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Solution for (4x+3)/2+x=(5x+4)/4 equation: 



(4x+3)/2+x=(5x+4)/4

We move all terms to the left:

(4x+3)/2+x-((5x+4)/4)=0

We add all the numbers together, and all the variables

x+(4x+3)/2-((5x+4)/4)=0

We calculate fractions


x+4x/()+(-((5x+4)*2)/()=0



We calculate terms in parentheses: +(-((5x+4)*2)/(), so:

-((5x+4)*2)/(

We multiply all the terms by the denominator


-((5x+4)*2)



We calculate terms in parentheses: -((5x+4)*2), so:

(5x+4)*2

We multiply parentheses

10x+8

Back to the equation:

-(10x+8)



We get rid of parentheses

-10x-8

Back to the equation:

+(-10x-8)



We get rid of parentheses

x+4x/()-10x-8=0

We multiply all the terms by the denominator


x*()+4x-10x*()-8*()=0

We add all the numbers together, and all the variables

4x+x*()-10x*()=0

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