(4x+3)/2+x=(5x+4)/4

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Solution for (4x+3)/2+x=(5x+4)/4 equation:



(4x+3)/2+x=(5x+4)/4
We move all terms to the left:
(4x+3)/2+x-((5x+4)/4)=0
We add all the numbers together, and all the variables
x+(4x+3)/2-((5x+4)/4)=0
We calculate fractions
x+4x/()+(-((5x+4)*2)/()=0
We calculate terms in parentheses: +(-((5x+4)*2)/(), so:
-((5x+4)*2)/(
We multiply all the terms by the denominator
-((5x+4)*2)
We calculate terms in parentheses: -((5x+4)*2), so:
(5x+4)*2
We multiply parentheses
10x+8
Back to the equation:
-(10x+8)
We get rid of parentheses
-10x-8
Back to the equation:
+(-10x-8)
We get rid of parentheses
x+4x/()-10x-8=0
We multiply all the terms by the denominator
x*()+4x-10x*()-8*()=0
We add all the numbers together, and all the variables
4x+x*()-10x*()=0

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