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(4x+3)/4-(2x)/x+1=x
We move all terms to the left:
(4x+3)/4-(2x)/x+1-(x)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
-1x+(4x+3)/4-2x/x+1=0
We calculate fractions
-1x+(4x^2+3x)/4x+(-8x)/4x+1=0
We multiply all the terms by the denominator
-1x*4x+(4x^2+3x)+(-8x)+1*4x=0
Wy multiply elements
-4x^2+(4x^2+3x)+(-8x)+4x=0
We get rid of parentheses
-4x^2+4x^2+3x-8x+4x=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
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