(4x+3)/5=(2x+1)/2

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Solution for (4x+3)/5=(2x+1)/2 equation:



(4x+3)/5=(2x+1)/2
We move all terms to the left:
(4x+3)/5-((2x+1)/2)=0
We calculate fractions
4x/()+(-((2x+1)*5)/()=0
We calculate terms in parentheses: +(-((2x+1)*5)/(), so:
-((2x+1)*5)/(
We multiply all the terms by the denominator
-((2x+1)*5)
We calculate terms in parentheses: -((2x+1)*5), so:
(2x+1)*5
We multiply parentheses
10x+5
Back to the equation:
-(10x+5)
We get rid of parentheses
-10x-5
Back to the equation:
+(-10x-5)
We get rid of parentheses
4x/()-10x-5=0
We multiply all the terms by the denominator
4x-10x*()-5*()=0
We add all the numbers together, and all the variables
4x-10x*()=0

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