(4x+3)/5=(2x+1)/2

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Solution for (4x+3)/5=(2x+1)/2 equation: 



(4x+3)/5=(2x+1)/2

We move all terms to the left:

(4x+3)/5-((2x+1)/2)=0

We calculate fractions


4x/()+(-((2x+1)*5)/()=0



We calculate terms in parentheses: +(-((2x+1)*5)/(), so:

-((2x+1)*5)/(

We multiply all the terms by the denominator


-((2x+1)*5)



We calculate terms in parentheses: -((2x+1)*5), so:

(2x+1)*5

We multiply parentheses

10x+5

Back to the equation:

-(10x+5)



We get rid of parentheses

-10x-5

Back to the equation:

+(-10x-5)



We get rid of parentheses

4x/()-10x-5=0

We multiply all the terms by the denominator


4x-10x*()-5*()=0

We add all the numbers together, and all the variables

4x-10x*()=0

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