(4x+3)/6+(x/3)=2

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Solution for (4x+3)/6+(x/3)=2 equation: 



(4x+3)/6+(x/3)=2

We move all terms to the left:

(4x+3)/6+(x/3)-(2)=0

We add all the numbers together, and all the variables

(4x+3)/6+(+x/3)-2=0

We get rid of parentheses

(4x+3)/6+x/3-2=0

We calculate fractions

There is no solution for this equation

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