(4x+3)=9(x-2)-x

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Solution for (4x+3)=9(x-2)-x equation: 



(4x+3)=9(x-2)-x

We move all terms to the left:

(4x+3)-(9(x-2)-x)=0

We get rid of parentheses

4x-(9(x-2)-x)+3=0



We calculate terms in parentheses: -(9(x-2)-x), so:

9(x-2)-x

We add all the numbers together, and all the variables

-1x+9(x-2)

We multiply parentheses

-1x+9x-18

We add all the numbers together, and all the variables

8x-18

Back to the equation:

-(8x-18)



We get rid of parentheses

4x-8x+18+3=0

We add all the numbers together, and all the variables

-4x+21=0

We move all terms containing x to the left, all other terms to the right

-4x=-21

x=-21/-4

x=5+1/4

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