(4x+3)=9(x-2)-x

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Solution for (4x+3)=9(x-2)-x equation:



(4x+3)=9(x-2)-x
We move all terms to the left:
(4x+3)-(9(x-2)-x)=0
We get rid of parentheses
4x-(9(x-2)-x)+3=0
We calculate terms in parentheses: -(9(x-2)-x), so:
9(x-2)-x
We add all the numbers together, and all the variables
-1x+9(x-2)
We multiply parentheses
-1x+9x-18
We add all the numbers together, and all the variables
8x-18
Back to the equation:
-(8x-18)
We get rid of parentheses
4x-8x+18+3=0
We add all the numbers together, and all the variables
-4x+21=0
We move all terms containing x to the left, all other terms to the right
-4x=-21
x=-21/-4
x=5+1/4

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