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(4x+3)x=520
We move all terms to the left:
(4x+3)x-(520)=0
We multiply parentheses
4x^2+3x-520=0
a = 4; b = 3; c = -520;
Δ = b2-4ac
Δ = 32-4·4·(-520)
Δ = 8329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{8329}}{2*4}=\frac{-3-\sqrt{8329}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{8329}}{2*4}=\frac{-3+\sqrt{8329}}{8} $
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